35+3x=3(-x+5)-28

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Solution for 35+3x=3(-x+5)-28 equation: 



35+3x=3(-x+5)-28

We move all terms to the left:

35+3x-(3(-x+5)-28)=0

We add all the numbers together, and all the variables

3x-(3(-1x+5)-28)+35=0



We calculate terms in parentheses: -(3(-1x+5)-28), so:

3(-1x+5)-28

We multiply parentheses

-3x+15-28

We add all the numbers together, and all the variables

-3x-13

Back to the equation:

-(-3x-13)



We get rid of parentheses

3x+3x+13+35=0

We add all the numbers together, and all the variables

6x+48=0

We move all terms containing x to the left, all other terms to the right

6x=-48

x=-48/6

x=-8

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