35+4v=8(1-2v)7v

Solution for 35+4v=8(1-2v)7v equation:

35+4v=8(1-2v)7v

We move all terms to the left:

35+4v-(8(1-2v)7v)=0

We add all the numbers together, and all the variables

4v-(8(-2v+1)7v)+35=0


We calculate terms in parentheses: -(8(-2v+1)7v), so:

8(-2v+1)7v

We multiply parentheses

-112v^2+56v

Back to the equation:

-(-112v^2+56v)


We get rid of parentheses

112v^2-56v+4v+35=0

We add all the numbers together, and all the variables

112v^2-52v+35=0

a = 112; b = -52; c = +35;
Δ = b2-4ac
Δ = -522-4·112·35
Δ = -12976
Delta is less than zero, so there is no solution for the equation