35-(2c+3)=2(c+3)+c

Solution for 35-(2c+3)=2(c+3)+c equation:

Simplifying
35 + -1(2c + 3) = 2(c + 3) + c

Reorder the terms:
35 + -1(3 + 2c) = 2(c + 3) + c
35 + (3 * -1 + 2c * -1) = 2(c + 3) + c
35 + (-3 + -2c) = 2(c + 3) + c

Combine like terms: 35 + -3 = 32
32 + -2c = 2(c + 3) + c

Reorder the terms:
32 + -2c = 2(3 + c) + c
32 + -2c = (3 * 2 + c * 2) + c
32 + -2c = (6 + 2c) + c

Combine like terms: 2c + c = 3c
32 + -2c = 6 + 3c

Solving
32 + -2c = 6 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
32 + -2c + -3c = 6 + 3c + -3c

Combine like terms: -2c + -3c = -5c
32 + -5c = 6 + 3c + -3c

Combine like terms: 3c + -3c = 0
32 + -5c = 6 + 0
32 + -5c = 6

Add '-32' to each side of the equation.
32 + -32 + -5c = 6 + -32

Combine like terms: 32 + -32 = 0
0 + -5c = 6 + -32
-5c = 6 + -32

Combine like terms: 6 + -32 = -26
-5c = -26

Divide each side by '-5'.
c = 5.2

Simplifying
c = 5.2