35-(2c+3)=2(c+6)+6

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Solution for 35-(2c+3)=2(c+6)+6 equation: 



35-(2c+3)=2(c+6)+6

We move all terms to the left:

35-(2c+3)-(2(c+6)+6)=0

We get rid of parentheses

-2c-(2(c+6)+6)-3+35=0



We calculate terms in parentheses: -(2(c+6)+6), so:

2(c+6)+6

We multiply parentheses

2c+12+6

We add all the numbers together, and all the variables

2c+18

Back to the equation:

-(2c+18)



We add all the numbers together, and all the variables

-2c-(2c+18)+32=0

We get rid of parentheses

-2c-2c-18+32=0

We add all the numbers together, and all the variables

-4c+14=0

We move all terms containing c to the left, all other terms to the right

-4c=-14

c=-14/-4

c=3+1/2

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