35-(2c+4)=2(c+3)=c

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Solution for 35-(2c+4)=2(c+3)=c equation: 



35-(2c+4)=2(c+3)=c

We move all terms to the left:

35-(2c+4)-(2(c+3))=0

We get rid of parentheses

-2c-(2(c+3))-4+35=0



We calculate terms in parentheses: -(2(c+3)), so:

2(c+3)

We multiply parentheses

2c+6

Back to the equation:

-(2c+6)



We add all the numbers together, and all the variables

-2c-(2c+6)+31=0

We get rid of parentheses

-2c-2c-6+31=0

We add all the numbers together, and all the variables

-4c+25=0

We move all terms containing c to the left, all other terms to the right

-4c=-25

c=-25/-4

c=6+1/4

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