35-(2c+4)=29(c+3)+c

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Solution for 35-(2c+4)=29(c+3)+c equation: 



35-(2c+4)=29(c+3)+c

We move all terms to the left:

35-(2c+4)-(29(c+3)+c)=0

We get rid of parentheses

-2c-(29(c+3)+c)-4+35=0



We calculate terms in parentheses: -(29(c+3)+c), so:

29(c+3)+c

We add all the numbers together, and all the variables

c+29(c+3)

We multiply parentheses

c+29c+87

We add all the numbers together, and all the variables

30c+87

Back to the equation:

-(30c+87)



We add all the numbers together, and all the variables

-2c-(30c+87)+31=0

We get rid of parentheses

-2c-30c-87+31=0

We add all the numbers together, and all the variables

-32c-56=0

We move all terms containing c to the left, all other terms to the right

-32c=56

c=56/-32

c=-1+3/4

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