35-(3x+3)=3(x+6)+x

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Solution for 35-(3x+3)=3(x+6)+x equation: 



35-(3x+3)=3(x+6)+x

We move all terms to the left:

35-(3x+3)-(3(x+6)+x)=0

We get rid of parentheses

-3x-(3(x+6)+x)-3+35=0



We calculate terms in parentheses: -(3(x+6)+x), so:

3(x+6)+x

We add all the numbers together, and all the variables

x+3(x+6)

We multiply parentheses

x+3x+18

We add all the numbers together, and all the variables

4x+18

Back to the equation:

-(4x+18)



We add all the numbers together, and all the variables

-3x-(4x+18)+32=0

We get rid of parentheses

-3x-4x-18+32=0

We add all the numbers together, and all the variables

-7x+14=0

We move all terms containing x to the left, all other terms to the right

-7x=-14

x=-14/-7

x=+2

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