35-(6-4x)-(3x-2)=31x-(42x-22)

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Solution for 35-(6-4x)-(3x-2)=31x-(42x-22) equation: 



35-(6-4x)-(3x-2)=31x-(42x-22)

We move all terms to the left:

35-(6-4x)-(3x-2)-(31x-(42x-22))=0

We add all the numbers together, and all the variables

-(-4x+6)-(3x-2)-(31x-(42x-22))+35=0

We get rid of parentheses

4x-3x-(31x-(42x-22))-6+2+35=0



We calculate terms in parentheses: -(31x-(42x-22)), so:

31x-(42x-22)

We get rid of parentheses

31x-42x+22

We add all the numbers together, and all the variables

-11x+22

Back to the equation:

-(-11x+22)



We add all the numbers together, and all the variables

x-(-11x+22)+31=0

We get rid of parentheses

x+11x-22+31=0

We add all the numbers together, and all the variables

12x+9=0

We move all terms containing x to the left, all other terms to the right

12x=-9

x=-9/12

x=-3/4

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