35-20x=1-5(4x-3)

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Solution for 35-20x=1-5(4x-3) equation: 



35-20x=1-5(4x-3)

We move all terms to the left:

35-20x-(1-5(4x-3))=0



We calculate terms in parentheses: -(1-5(4x-3)), so:

1-5(4x-3)

determiningTheFunctionDomain
-5(4x-3)+1

We multiply parentheses

-20x+15+1

We add all the numbers together, and all the variables

-20x+16

Back to the equation:

-(-20x+16)



We get rid of parentheses

-20x+20x-16+35=0

We add all the numbers together, and all the variables

19!=0

There is no solution for this equation

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