35-b=-2b-3(b-1)

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Solution for 35-b=-2b-3(b-1) equation: 



35-b=-2b-3(b-1)

We move all terms to the left:

35-b-(-2b-3(b-1))=0

We add all the numbers together, and all the variables

-1b-(-2b-3(b-1))+35=0



We calculate terms in parentheses: -(-2b-3(b-1)), so:

-2b-3(b-1)

We multiply parentheses

-2b-3b+3

We add all the numbers together, and all the variables

-5b+3

Back to the equation:

-(-5b+3)



We get rid of parentheses

-1b+5b-3+35=0

We add all the numbers together, and all the variables

4b+32=0

We move all terms containing b to the left, all other terms to the right

4b=-32

b=-32/4

b=-8

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