35/(c+2)=7

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Solution for 35/(c+2)=7 equation: 


D( c )

c+2 = 0

c+2 = 0

c+2 = 0

c+2 = 0 // - 2

c = -2

c in (-oo:-2) U (-2:+oo)

35/(c+2) = 7 // - 7

35/(c+2)-7 = 0

35/(c+2)+(-7*(c+2))/(c+2) = 0

35-7*(c+2) = 0

21-7*c = 0

(21-7*c)/(c+2) = 0

(21-7*c)/(c+2) = 0 // * c+2

21-7*c = 0

21-7*c = 0 // - 21

-7*c = -21 // : -7

c = -21/(-7)

c = 3

c = 3

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