35/n=1

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Solution for 35/n=1 equation:


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

35/n = 1 // - 1

35/n-1 = 0

35*n^-1 = 1 // : 35

n^-1 = 1/35

-1 < 0

1/(n^1) = 1/35 // * n^1

1 = 1/35*n^1 // : 1/35

35 = n^1

n = 35

n = 35

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