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35/x-35/(x+0.5)=5/3
We move all terms to the left:
35/x-35/(x+0.5)-(5/3)=0
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+0.5)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-0.5
x∈R
35/x-35/(x+0.5)-(+5/3)=0
We get rid of parentheses
35/x-35/(x+0.5)-5/3=0
We calculate fractions
(-5x^2*()/(3x^2+1.5x)+(105x+52.5)/(3x^2+1.5x)+(-315x)/(3x^2+1.5x)=0
We calculate terms in parentheses: +(-5x^2*()/(3x^2+1.5x)+(105x+52.5)/(3x^2+1.5x)+(-315x)/(3x^2+1.5x), so:
-5x^2*()/(3x^2+1.5x)+(105x+52.5)/(3x^2+1.5x)+(-315x)/(3x^2+1.5x
We calculate fractions
(-5x^2*()+(105x+52.5)*(3x^2+1.5x)/((3x^2+1.5x)*(3x^2+1.5x)+((-315x)*(3x^2+1.5x))/((3x^2+1.5x)*(3x^2+1.5x)
We calculate terms in parentheses: +(-5x^2*()+(105x+52.5)*(3x^2+1.5x)/((3x^2+1.5x)*(3x^2+1.5x)+((-315x)*(3x^2+1.5x))/((3x^2+1.5x)*(3x^2+1.5x), so:
-5x^2*()+(105x+52.5)*(3x^2+1.5x)/((3x^2+1.5x)*(3x^2+1.5x)+((-315x)*(3x^2+1.5x))/((3x^2+1.5x)*(3x^2+1.5x
We can not solve this equation
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