350=2l+(2l/3)

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Solution for 350=2l+(2l/3) equation: 



350=2l+(2l/3)

We move all terms to the left:

350-(2l+(2l/3))=0

We add all the numbers together, and all the variables

-(2l+(+2l/3))+350=0

We multiply all the terms by the denominator


-(2l+(+2l+350*3))=0



We calculate terms in parentheses: -(2l+(+2l+350*3)), so:

2l+(+2l+350*3)

We add all the numbers together, and all the variables

2l+(2l+1050)

We get rid of parentheses

2l+2l+1050

We add all the numbers together, and all the variables

4l+1050

Back to the equation:

-(4l+1050)



We get rid of parentheses

-4l-1050=0

We move all terms containing l to the left, all other terms to the right

-4l=1050

l=1050/-4

l=-262+1/2

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