350=4x+5(3x+32)

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Solution for 350=4x+5(3x+32) equation: 



350=4x+5(3x+32)

We move all terms to the left:

350-(4x+5(3x+32))=0



We calculate terms in parentheses: -(4x+5(3x+32)), so:

4x+5(3x+32)

We multiply parentheses

4x+15x+160

We add all the numbers together, and all the variables

19x+160

Back to the equation:

-(19x+160)



We get rid of parentheses

-19x-160+350=0

We add all the numbers together, and all the variables

-19x+190=0

We move all terms containing x to the left, all other terms to the right

-19x=-190

x=-190/-19

x=+10

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