35=(1)/(2)h(4+3)

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Solution for 35=(1)/(2)h(4+3) equation: 



35=(1)/(2)h(4+3)

We move all terms to the left:

35-((1)/(2)h(4+3))=0



Domain of the equation: 2h(4+3))!=0

h∈R



We add all the numbers together, and all the variables

-(1/2h7)+35=0

We get rid of parentheses

-1/2h7+35=0

We multiply all the terms by the denominator


35*2h7-1=0

Wy multiply elements

70h^7-1=0

We do not support ehpression: h^7

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