35=(2x)2+x/2

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Solution for 35=(2x)2+x/2 equation: 


x in (-oo:+oo)

35 = (2*x)^2+x/2 // - (2*x)^2+x/2

35-(2*x)^2-(x/2) = 0

35-x^2-1/2*x = 0

DELTA = (-1/2)^2-(-1*4*35)

DELTA = 561/4

DELTA > 0

x = ((561/4)^(1/2)+1/2)/(-1*2) or x = (1/2-(561/4)^(1/2))/(-1*2)

x = ((561/4)^(1/2)+1/2)/(-2) or x = (1/2-(561/4)^(1/2))/(-2)

x in { ((561/4)^(1/2)+1/2)/(-2), (1/2-(561/4)^(1/2))/(-2) }

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