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35=(5/7)v
We move all terms to the left:
35-((5/7)v)=0
Domain of the equation: 7)v)!=0We add all the numbers together, and all the variables
v!=0/1
v!=0
v∈R
-((+5/7)v)+35=0
We multiply all the terms by the denominator
-((+5+35*7)v)=0
We calculate terms in parentheses: -((+5+35*7)v), so:v=0/-250
(+5+35*7)v
We add all the numbers together, and all the variables
250v
Back to the equation:
-(250v)
v=0
Równanie nie ma rozwiązania
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