35=-7(4v-5)+28v

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Solution for 35=-7(4v-5)+28v equation: 



35=-7(4v-5)+28v

We move all terms to the left:

35-(-7(4v-5)+28v)=0



We calculate terms in parentheses: -(-7(4v-5)+28v), so:

-7(4v-5)+28v

We add all the numbers together, and all the variables

28v-7(4v-5)

We multiply parentheses

28v-28v+35

We add all the numbers together, and all the variables

35

Back to the equation:

-(35)



We add all the numbers together, and all the variables

=0

v=0/1

v=0

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