35=1/5(20x-15)

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Solution for 35=1/5(20x-15) equation: 



35=1/5(20x-15)

We move all terms to the left:

35-(1/5(20x-15))=0



Domain of the equation: 5(20x-15))!=0

x∈R



We multiply all the terms by the denominator


-(1+35*5(20x-15))=0



We calculate terms in parentheses: -(1+35*5(20x-15)), so:

1+35*5(20x-15)

determiningTheFunctionDomain
35*5(20x-15)+1

Wy multiply elements

175x(2+1

Back to the equation:

-(175x(2+1)



We add all the numbers together, and all the variables

-(175x3=0

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