35=10(x+5)-2

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Solution for 35=10(x+5)-2 equation: 



35=10(x+5)-2

We move all terms to the left:

35-(10(x+5)-2)=0



We calculate terms in parentheses: -(10(x+5)-2), so:

10(x+5)-2

We multiply parentheses

10x+50-2

We add all the numbers together, and all the variables

10x+48

Back to the equation:

-(10x+48)



We get rid of parentheses

-10x-48+35=0

We add all the numbers together, and all the variables

-10x-13=0

We move all terms containing x to the left, all other terms to the right

-10x=13

x=13/-10

x=-1+3/10

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