35=10-(-7+2v)

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Solution for 35=10-(-7+2v) equation:



35=10-(-7+2v)
We move all terms to the left:
35-(10-(-7+2v))=0
We add all the numbers together, and all the variables
-(10-(2v-7))+35=0
We calculate terms in parentheses: -(10-(2v-7)), so:
10-(2v-7)
determiningTheFunctionDomain -(2v-7)+10
We get rid of parentheses
-2v+7+10
We add all the numbers together, and all the variables
-2v+17
Back to the equation:
-(-2v+17)
We get rid of parentheses
2v-17+35=0
We add all the numbers together, and all the variables
2v+18=0
We move all terms containing v to the left, all other terms to the right
2v=-18
v=-18/2
v=-9

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