35=12x(8x-7)

Solution for 35=12x(8x-7) equation:

35=12x(8x-7)

We move all terms to the left:

35-(12x(8x-7))=0


We calculate terms in parentheses: -(12x(8x-7)), so:

12x(8x-7)

We multiply parentheses

96x^2-84x

Back to the equation:

-(96x^2-84x)


We get rid of parentheses

-96x^2+84x+35=0

a = -96; b = 84; c = +35;
Δ = b2-4ac
Δ = 842-4·(-96)·35
Δ = 20496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{20496}=\sqrt{16*1281}=\sqrt{16}*\sqrt{1281}=4\sqrt{1281}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-4\sqrt{1281}}{2*-96}=\frac{-84-4\sqrt{1281}}{-192}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+4\sqrt{1281}}{2*-96}=\frac{-84+4\sqrt{1281}}{-192}
$