35=19-4(5+d)

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Solution for 35=19-4(5+d) equation: 



35=19-4(5+d)

We move all terms to the left:

35-(19-4(5+d))=0

We add all the numbers together, and all the variables

-(19-4(d+5))+35=0



We calculate terms in parentheses: -(19-4(d+5)), so:

19-4(d+5)

determiningTheFunctionDomain
-4(d+5)+19

We multiply parentheses

-4d-20+19

We add all the numbers together, and all the variables

-4d-1

Back to the equation:

-(-4d-1)



We get rid of parentheses

4d+1+35=0

We add all the numbers together, and all the variables

4d+36=0

We move all terms containing d to the left, all other terms to the right

4d=-36

d=-36/4

d=-9

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