35=2(x-5)-7x

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Solution for 35=2(x-5)-7x equation: 



35=2(x-5)-7x

We move all terms to the left:

35-(2(x-5)-7x)=0



We calculate terms in parentheses: -(2(x-5)-7x), so:

2(x-5)-7x

We add all the numbers together, and all the variables

-7x+2(x-5)

We multiply parentheses

-7x+2x-10

We add all the numbers together, and all the variables

-5x-10

Back to the equation:

-(-5x-10)



We get rid of parentheses

5x+10+35=0

We add all the numbers together, and all the variables

5x+45=0

We move all terms containing x to the left, all other terms to the right

5x=-45

x=-45/5

x=-9

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