35=28-2/5y

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Solution for 35=28-2/5y equation: 



35=28-2/5y

We move all terms to the left:

35-(28-2/5y)=0



Domain of the equation: 5y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

-(-2/5y+28)+35=0

We get rid of parentheses

2/5y-28+35=0

We multiply all the terms by the denominator


-28*5y+35*5y+2=0

Wy multiply elements

-140y+175y+2=0

We add all the numbers together, and all the variables

35y+2=0

We move all terms containing y to the left, all other terms to the right

35y=-2

y=-2/35

y=-2/35

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