35=3(10i-9)+2

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Solution for 35=3(10i-9)+2 equation: 



35=3(10i-9)+2

We move all terms to the left:

35-(3(10i-9)+2)=0



We calculate terms in parentheses: -(3(10i-9)+2), so:

3(10i-9)+2

We multiply parentheses

30i-27+2

We add all the numbers together, and all the variables

30i-25

Back to the equation:

-(30i-25)



We get rid of parentheses

-30i+25+35=0

We add all the numbers together, and all the variables

-30i+60=0

We move all terms containing i to the left, all other terms to the right

-30i=-60

i=-60/-30

i=+2

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