35=3(5r+7)-1

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Solution for 35=3(5r+7)-1 equation: 



35=3(5r+7)-1

We move all terms to the left:

35-(3(5r+7)-1)=0



We calculate terms in parentheses: -(3(5r+7)-1), so:

3(5r+7)-1

We multiply parentheses

15r+21-1

We add all the numbers together, and all the variables

15r+20

Back to the equation:

-(15r+20)



We get rid of parentheses

-15r-20+35=0

We add all the numbers together, and all the variables

-15r+15=0

We move all terms containing r to the left, all other terms to the right

-15r=-15

r=-15/-15

r=1

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