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35=3(x-5)-8x
We move all terms to the left:
35-(3(x-5)-8x)=0
We calculate terms in parentheses: -(3(x-5)-8x), so:We get rid of parentheses
3(x-5)-8x
We add all the numbers together, and all the variables
-8x+3(x-5)
We multiply parentheses
-8x+3x-15
We add all the numbers together, and all the variables
-5x-15
Back to the equation:
-(-5x-15)
5x+15+35=0
We add all the numbers together, and all the variables
5x+50=0
We move all terms containing x to the left, all other terms to the right
5x=-50
x=-50/5
x=-10
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