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35=3-2(t+2)
We move all terms to the left:
35-(3-2(t+2))=0
We calculate terms in parentheses: -(3-2(t+2)), so:We get rid of parentheses
3-2(t+2)
determiningTheFunctionDomain -2(t+2)+3
We multiply parentheses
-2t-4+3
We add all the numbers together, and all the variables
-2t-1
Back to the equation:
-(-2t-1)
2t+1+35=0
We add all the numbers together, and all the variables
2t+36=0
We move all terms containing t to the left, all other terms to the right
2t=-36
t=-36/2
t=-18
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