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35=3/5(x+10)
We move all terms to the left:
35-(3/5(x+10))=0
Domain of the equation: 5(x+10))!=0We multiply all the terms by the denominator
x∈R
-(3+35*5(x+10))=0
We calculate terms in parentheses: -(3+35*5(x+10)), so:
3+35*5(x+10)
determiningTheFunctionDomain 35*5(x+10)+3
Wy multiply elements
175x(x+3
Back to the equation:
-(175x(x+3)
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