35=4(x-7)+5x

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Solution for 35=4(x-7)+5x equation: 



35=4(x-7)+5x

We move all terms to the left:

35-(4(x-7)+5x)=0



We calculate terms in parentheses: -(4(x-7)+5x), so:

4(x-7)+5x

We add all the numbers together, and all the variables

5x+4(x-7)

We multiply parentheses

5x+4x-28

We add all the numbers together, and all the variables

9x-28

Back to the equation:

-(9x-28)



We get rid of parentheses

-9x+28+35=0

We add all the numbers together, and all the variables

-9x+63=0

We move all terms containing x to the left, all other terms to the right

-9x=-63

x=-63/-9

x=+7

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