35=4+5(n+7)

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Solution for 35=4+5(n+7) equation: 



35=4+5(n+7)

We move all terms to the left:

35-(4+5(n+7))=0



We calculate terms in parentheses: -(4+5(n+7)), so:

4+5(n+7)

determiningTheFunctionDomain
5(n+7)+4

We multiply parentheses

5n+35+4

We add all the numbers together, and all the variables

5n+39

Back to the equation:

-(5n+39)



We get rid of parentheses

-5n-39+35=0

We add all the numbers together, and all the variables

-5n-4=0

We move all terms containing n to the left, all other terms to the right

-5n=4

n=4/-5

n=-4/5

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