35=4b+(b+2)+b

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Solution for 35=4b+(b+2)+b equation: 



35=4b+(b+2)+b

We move all terms to the left:

35-(4b+(b+2)+b)=0



We calculate terms in parentheses: -(4b+(b+2)+b), so:

4b+(b+2)+b

We add all the numbers together, and all the variables

5b+(b+2)

We get rid of parentheses

5b+b+2

We add all the numbers together, and all the variables

6b+2

Back to the equation:

-(6b+2)



We get rid of parentheses

-6b-2+35=0

We add all the numbers together, and all the variables

-6b+33=0

We move all terms containing b to the left, all other terms to the right

-6b=-33

b=-33/-6

b=5+1/2

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