35=4b+(b+2)+b

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Solution for 35=4b+(b+2)+b equation:



35=4b+(b+2)+b
We move all terms to the left:
35-(4b+(b+2)+b)=0
We calculate terms in parentheses: -(4b+(b+2)+b), so:
4b+(b+2)+b
We add all the numbers together, and all the variables
5b+(b+2)
We get rid of parentheses
5b+b+2
We add all the numbers together, and all the variables
6b+2
Back to the equation:
-(6b+2)
We get rid of parentheses
-6b-2+35=0
We add all the numbers together, and all the variables
-6b+33=0
We move all terms containing b to the left, all other terms to the right
-6b=-33
b=-33/-6
b=5+1/2

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