35=5(2x-1)

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Solution for 35=5(2x-1) equation: 



35=5(2x-1)

We move all terms to the left:

35-(5(2x-1))=0



We calculate terms in parentheses: -(5(2x-1)), so:

5(2x-1)

We multiply parentheses

10x-5

Back to the equation:

-(10x-5)



We get rid of parentheses

-10x+5+35=0

We add all the numbers together, and all the variables

-10x+40=0

We move all terms containing x to the left, all other terms to the right

-10x=-40

x=-40/-10

x=+4

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