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35=5(3-2x)
We move all terms to the left:
35-(5(3-2x))=0
We add all the numbers together, and all the variables
-(5(-2x+3))+35=0
We calculate terms in parentheses: -(5(-2x+3)), so:We get rid of parentheses
5(-2x+3)
We multiply parentheses
-10x+15
Back to the equation:
-(-10x+15)
10x-15+35=0
We add all the numbers together, and all the variables
10x+20=0
We move all terms containing x to the left, all other terms to the right
10x=-20
x=-20/10
x=-2
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