35=5(v-2)+4v

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Solution for 35=5(v-2)+4v equation: 



35=5(v-2)+4v

We move all terms to the left:

35-(5(v-2)+4v)=0



We calculate terms in parentheses: -(5(v-2)+4v), so:

5(v-2)+4v

We add all the numbers together, and all the variables

4v+5(v-2)

We multiply parentheses

4v+5v-10

We add all the numbers together, and all the variables

9v-10

Back to the equation:

-(9v-10)



We get rid of parentheses

-9v+10+35=0

We add all the numbers together, and all the variables

-9v+45=0

We move all terms containing v to the left, all other terms to the right

-9v=-45

v=-45/-9

v=+5

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