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35=5(x-32)/9+2
We move all terms to the left:
35-(5(x-32)/9+2)=0
We multiply all the terms by the denominator
-(5(x-32)+35*9+2)=0
We calculate terms in parentheses: -(5(x-32)+35*9+2), so:We get rid of parentheses
5(x-32)+35*9+2
determiningTheFunctionDomain 5(x-32)+2+35*9
We add all the numbers together, and all the variables
5(x-32)+317
We multiply parentheses
5x-160+317
We add all the numbers together, and all the variables
5x+157
Back to the equation:
-(5x+157)
-5x-157=0
We move all terms containing x to the left, all other terms to the right
-5x=157
x=157/-5
x=-31+2/5
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