35=6(1+3r)-6r

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Solution for 35=6(1+3r)-6r equation: 



35=6(1+3r)-6r

We move all terms to the left:

35-(6(1+3r)-6r)=0

We add all the numbers together, and all the variables

-(6(3r+1)-6r)+35=0



We calculate terms in parentheses: -(6(3r+1)-6r), so:

6(3r+1)-6r

We add all the numbers together, and all the variables

-6r+6(3r+1)

We multiply parentheses

-6r+18r+6

We add all the numbers together, and all the variables

12r+6

Back to the equation:

-(12r+6)



We get rid of parentheses

-12r-6+35=0

We add all the numbers together, and all the variables

-12r+29=0

We move all terms containing r to the left, all other terms to the right

-12r=-29

r=-29/-12

r=2+5/12

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