35=7(n-5)+2(5n+1)

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Solution for 35=7(n-5)+2(5n+1) equation: 



35=7(n-5)+2(5n+1)

We move all terms to the left:

35-(7(n-5)+2(5n+1))=0



We calculate terms in parentheses: -(7(n-5)+2(5n+1)), so:

7(n-5)+2(5n+1)

We multiply parentheses

7n+10n-35+2

We add all the numbers together, and all the variables

17n-33

Back to the equation:

-(17n-33)



We get rid of parentheses

-17n+33+35=0

We add all the numbers together, and all the variables

-17n+68=0

We move all terms containing n to the left, all other terms to the right

-17n=-68

n=-68/-17

n=+4

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