35=8(4y-3)-5

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Solution for 35=8(4y-3)-5 equation:



35=8(4y-3)-5
We move all terms to the left:
35-(8(4y-3)-5)=0
We calculate terms in parentheses: -(8(4y-3)-5), so:
8(4y-3)-5
We multiply parentheses
32y-24-5
We add all the numbers together, and all the variables
32y-29
Back to the equation:
-(32y-29)
We get rid of parentheses
-32y+29+35=0
We add all the numbers together, and all the variables
-32y+64=0
We move all terms containing y to the left, all other terms to the right
-32y=-64
y=-64/-32
y=+2

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