35=c+(c+9)+(c-8)

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Solution for 35=c+(c+9)+(c-8) equation: 



35=c+(c+9)+(c-8)

We move all terms to the left:

35-(c+(c+9)+(c-8))=0



We calculate terms in parentheses: -(c+(c+9)+(c-8)), so:

c+(c+9)+(c-8)

We get rid of parentheses

c+c+c+9-8

We add all the numbers together, and all the variables

3c+1

Back to the equation:

-(3c+1)



We get rid of parentheses

-3c-1+35=0

We add all the numbers together, and all the variables

-3c+34=0

We move all terms containing c to the left, all other terms to the right

-3c=-34

c=-34/-3

c=11+1/3

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