35cos(3y+15)+10=2

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Solution for 35cos(3y+15)+10=2 equation: 


Simplifying
35cos(3y + 15) + 10 = 2

Reorder the terms:
35cos(15 + 3y) + 10 = 2
(15 * 35cos + 3y * 35cos) + 10 = 2
(525cos + 105cosy) + 10 = 2

Reorder the terms:
10 + 525cos + 105cosy = 2

Solving
10 + 525cos + 105cosy = 2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + 525cos + -10 + 105cosy = 2 + -10

Reorder the terms:
10 + -10 + 525cos + 105cosy = 2 + -10

Combine like terms: 10 + -10 = 0
0 + 525cos + 105cosy = 2 + -10
525cos + 105cosy = 2 + -10

Combine like terms: 2 + -10 = -8
525cos + 105cosy = -8

Reorder the terms:
8 + 525cos + 105cosy = -8 + 8

Combine like terms: -8 + 8 = 0
8 + 525cos + 105cosy = 0

The solution to this equation could not be determined.

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