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35k^2+4k=0
a = 35; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·35·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*35}=\frac{-8}{70} =-4/35 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*35}=\frac{0}{70} =0 $
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