35n2+250n-240=0

Solution for 35n2+250n-240=0 equation:

35n^2+250n-240=0

a = 35; b = 250; c = -240;
Δ = b2-4ac
Δ = 2502-4·35·(-240)
Δ = 96100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{96100}=310$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-310}{2*35}=\frac{-560}{70}
=-8
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+310}{2*35}=\frac{60}{70}
=6/7
$