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35p^2-19p+2=0
a = 35; b = -19; c = +2;
Δ = b2-4ac
Δ = -192-4·35·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-9}{2*35}=\frac{10}{70} =1/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+9}{2*35}=\frac{28}{70} =2/5 $
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