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35x^2+22x+3=0
a = 35; b = 22; c = +3;
Δ = b2-4ac
Δ = 222-4·35·3
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-8}{2*35}=\frac{-30}{70} =-3/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+8}{2*35}=\frac{-14}{70} =-1/5 $
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