35x2+31x+6=0

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Solution for 35x2+31x+6=0 equation:



35x^2+31x+6=0
a = 35; b = 31; c = +6;
Δ = b2-4ac
Δ = 312-4·35·6
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-11}{2*35}=\frac{-42}{70} =-3/5 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+11}{2*35}=\frac{-20}{70} =-2/7 $

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