35x2-47x+6=-2

Solution for 35x2-47x+6=-2 equation:

35x^2-47x+6=-2

We move all terms to the left:

35x^2-47x+6-(-2)=0

We add all the numbers together, and all the variables

35x^2-47x+8=0

a = 35; b = -47; c = +8;
Δ = b2-4ac
Δ = -472-4·35·8
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47)-33}{2*35}=\frac{14}{70}
=1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47)+33}{2*35}=\frac{80}{70}
=1+1/7
$