35x2=13x+12

Solution for 35x2=13x+12 equation:

35x^2=13x+12

We move all terms to the left:

35x^2-(13x+12)=0

We get rid of parentheses

35x^2-13x-12=0

a = 35; b = -13; c = -12;
Δ = b2-4ac
Δ = -132-4·35·(-12)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-43}{2*35}=\frac{-30}{70}
=-3/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+43}{2*35}=\frac{56}{70}
=4/5
$